Task 5.1e


Which of the following are spontaneous disproportionation reactions?
(a) 3MnO42-(aq) 4H+(aq) ---> MnO2(s) + 2MnO4-(aq) + 2H2O(l)
(b) 2MnO4-(aq) + 16H+(aq) + 5C2O42-(aq) ---> 2Mn2+(aq) + 8H2O(l) + 10CO2(g)
(c) 3HNO2(aq) ----> HNO3(aq) + 2NO(g) + H2O(l)

CO2 + H+ +e- ---> 1/2 H2C2O4  Eo = +0.49V
MnO4-(aq) +e-  ---> MnO42-(aq) Eo = +0.60V
MnO4-(aq) +8H+ + 5e-  ---> Mn2+(aq) + 4H2O(l) Eo = +0.60V
MnO42-(aq) 4H+(aq) + 2e- = MnO2(s)  + 2H2O(l) Eo = +1.55V
NO3-(aq) + 3H+(aq) +2e- = HNO2(aq) + H2O(l)  Eo = +0.94V
HNO2(aq) + H+(aq) +e- = NO(g) + H2O(l)              Eo = +0.99V

 

 

 

 

 

 

 

 

Answers: (a) disproportionation, (b) not disproportionation, (c) disproportionation