Task 2.1f.2

1. Calculate the enthalpy change for the reaction:  (answer = -137kJmol-1)
C2H4(g)(g) + H2(g) ---> C2H6(g)
given the following standard enthalpies of combustion:
DHoc (C2H4(g)) = - 1411Jmol-1
DHoc(H2(g))      =  - 286kJmol-1
DHoc (C2H6(g)) =  - 1560kJmol-1

2. Calculate the standard enthalpy change of formation of methane from the following enthalpies of combustion. (answer = -76kJmol-1)
DHoc (CH4(g))   = - 890Jmol-1
DHoc(H2(g))      =  - 286kJmol-1
DHoc (C(s))       =  - 394kJmol-1

3. Calculate the standard enthalpy of formation of ethanol, C2H5OH, from the following standard enthalpies of combustion:
DHoc (C2H5OH(l))   = - 1367Jmol-1
DHoc(H2(g))            =  - 286kJmol-1
DHoc (C(s))             =  - 394kJmol-1


4. Methanol can be made in a two-step process.
Step 1:  CH4(g) +H2O(g) == CO(g) + 3H2(g)
Step 2:  CO(g) + 2H2(g) == CH3OH(g)
Use the following enthalpies of combustion to calculate the enthalpies of reaction for each of the steps:
DHoc (CH4(g))   = - 890mol-1
DHoc(H2(g))      =  - 245kJmol-1
DHoc (CO(g))       =  - 283kJmol-1

DHoc (CH3OH(g))   = - 671Jmol-1