1.7a Physical properties of the elements
They have characteristic odours and colours.
| property | fluorine | chorine | bromine | iodine |
| colour | pale yellow | yellow/green | red | black |
| colour in water | yellow/green | orange | brown | |
| colour in organic | red | purple | ||
| physical state | gas | gas | liquid | solid |
| water solubility | reacts | high | moderate | low (high in I-) |
| property | trend | factors |
| bond dissociation enthalpy | decreases Cl to I but F very low | internuclear distance (lone pair repulsion in F) |
| atomic radius | increases down group | extra energy levels |
| electron affinity | becomes more -ve up group | nucleus to electron distance |
| Melting and boiling points | increase down the group | van der waals forces increase with number of electrons |
1.7b Chemical tests for the elements
Chlorine turns blue litmus red then bleaches it. Chlorine displaces
bromine and iodine from bromide or iodide solutions.
Cl2(aq) + 2KBr(aq) ---> 2KCl(aq) + Br2(aq)
Cl2(aq) + 2KI(aq) ---> 2KCl(aq) + I2(aq)
Bromine is red if dissolved in an organic solvent. Bromine displaces
iodine from an iodide solution.
Br2(aq) + 2KI(aq) ---> 2KBr(aq) + I2(aq)
Iodine turns starch black, is decolourised by thiosulphate solution
and is brown in water but purple in organic solvents.
See
reactions here
Task 1.7b
Describe what you would see and explain the observations for making the
following mixtures
(a) chlorine + sodium bromide, (b) iodine and sodium chloride (c) bromine and
sodium iodide.
1.7c Hydrogen halides in water
Hydrogen chloride, hydrogen bromide and hydrogen iodide are all very
soluble as water molecules pull hydrogen ions away from HCl.
H2OD- ..... H+
HCl is strongly acidic due to complete dissociation.
HX(aq) + H2O(l) -----> H3O+(aq) +
X-(aq)
Hydrogen ions H+ or H3O+ provide
the acidity.
relative acid strength is HF << HCl < HBr < HI.
HI strongest as H-I bond is the longest weakest bond (299kJmol-1 for
H-I compared to 366kJmol-1 for H-Br, 431kJmol-1 for H-Cl
and 562kJmol-1 for H-F). HF is also less dissociated because of
the following interaction
H-F(aq) + F-(aq) --> [F----H-F]-(aq) HF does
attack glass but only because it is able to form the soluble ion SiF62-
and this is not an acid base reaction.
Task 1.7c State and explain the bond strengths in
H-X. Explain the relative acid strengths of (i)
HBr and HCl. (ii) HCl and HF.
1.7d The identification of chloride, bromide and iodide ions
Adding aqueous silver nitrate to an aqueous halides mixed with nitric
acid forms a silver halides.
Ag+(aq) + X-(aq) -----> AgX(s)
Silver chloride is white, silver bromide is buff colour and silver
iodide is yellow. The silver halides are unstable in the presence
of sunlight. They decompose forming silver (seen as dark specs) and the
halogen, for example:
2AgI(s) ----> 2Ag(s) + I2(s)
Silver chloride dissolves in dilute ammonia. Precipitates of silver chloride and silver bromide react with
conc. ammonia solution to form the diammine silver(I)ion
[Ag(NH3)2]+(aq) so the precipitates dissolve.
Silver iodide does not dissolve in even conc. ammonia solution.
Task 1.7d
Write balanced chemical and ionic equations for the reactions of aqueous
solutions of:
(i) sodium chloride and silver nitrate, (ii) lithium bromide and silver nitrate,
(iii) potassium iodide and silver nitrate, (iv) silver chloride and ammonia.
1.7e Halide salts with concentrated sulphuric acid
Hydrogen chloride is more volatile than the sulphuric acid (or hydrogen
sulphate). Therefore concentrated H2SO4 displaces
hydrogen chloride from sodium chloride:
NaCl(s) + H2SO4(l) ----> NaHSO4(s)
+ HCl(g). displacement
HBr can similarly be displaced from KBr but some of the HBr is oxidised
by the sulphuric acid.
KBr(s) + H2SO4(l) ----> KHSO4(s) + HBr(g) displacement
2HBr(g) + H2SO4(l) ----> Br2(aq) +
2H2O + SO2(g) oxidation of HBr
Conc. sulphuric acid also oxidises HI but the reaction goes further
as HI is a better reducing agent. Hydrogen sulfide has a rotten egg smell.
8HI(g) + H2SO4(l) ----> 2I2(s) + H2S(g)
+ 4H2O(l) oxidation of HI
Task 1.7e Describe observations and write balanced
chemical equations for:
(i) lithium chloride + conc. sulfuric acid, (ii) sodium bromide + conc. sulfuric
acid,
(iii) potassium iodide + conc. sulfuric acid.
1.7f The +1 and +5 oxidation states of chlorine
All the halogens except for fluorine exhibit a number of positive oxidation
states. These are due to the promotion of electrons from p orbitals into
vacant d orbitals. Chloric (I) acid HClO forms salts called chlorate(I)'s
e.g. NaClO. which contain the ion ClO- . Chloric acid
(V) HClO3 forms a series of salts called chlorate(V)'s.
For example sodium chlorate(V), NaClO3 contains the ion ClO3-.
These salts and acids are all good oxidising agents.
Story 1.7f
Task 1.7f Write formulae for the following:
sodium chlorate(I), potassium chlorate(V), sodium bromate(V) and potassium
iodate(V).
1.7g Disproportionation of chlorine
Disproportionation is the simultaneous oxidation and reduction of atoms of the same
element in the same reaction. Chlorine (ox. no. = 0) disproportionates in water
or alkali to form chloride (ox no. =-1) and chlorate(I) ions (ox. no. =
+1).
Cl2(g) + 2H2O(l) ----> Cl-(aq) + H3O+(aq)
+ HClO(aq)
Cl2(g) + 2OH-(aq) -----> Cl-(aq) +
ClO-(aq) + H2O(l).
Further disproportionation of ClO- can now occur on heating to form
chlorate(V) ions.
3ClO-(aq) -----> 2Cl-(aq) + ClO3-(aq)
Task 1.7g Write equations to show how
chlorine reacts with water and with sodium hydroxide. Explain how these
are both example of disproportionation. Explain how potassium bromate(I)
might disproportionate in aqueous solution.
1.7h Halogens as oxidising agents and bromine extraction
Oxidising power of the halogens decrease down the group.
Chlorine is therefore more strongly oxidising than bromine.
Bromine is extracted from
sea water at Amlwch in Anglesey in North Wales.
The raw materials are sea water (0.0065% by mass bromine) chlorine and sulphur
dioxide.
Evaporation concentrates the salts containing bromides. Acid is added to the sea water to drop its pH to 3.5. This
prevents bromine reacting with water later in the process.
Chlorine gas is passed through the sea water when bromide ions are oxidised to
bromine.
Cl2(g) + 2Br-(aq) -----> 2Cl-(aq)
+ Br2(aq)
Reactions of chlorine and bromine with water are prevented by the acidic conditions which
force the following equilibria to the left.
Cl2(aq) + H2O <--> HClO(aq) +H+(aq) + Cl-(aq)
Br2(aq) + H2O <--> HBrO(aq) +H+(aq) + Br-(aq)
Air is blasted into the solution causing a stream of bromine gas in moist air to
be formed.
The bromine gas formed is reduced with sulphur dioxide to form a solution of hydrobromic
acid.
Finally this solution (now containing 13% bromine) is treated with chlorine
again to convert the bromide to molecular bromine. It is separated by
distillation.
Task 1.7h Draw a flow chart showing bromine
manufacture with formulae of all substances involved shown entering, exiting or
flowing through the system.