Combine the following half equations to give balanced ionic redox equations:
(a) iron II and chlorine
Fe2+(aq) ----> Fe3+(aq) + e-
Cl2(aq) + 2e- -----> 2Cl-(aq)
(b) manganate VII and iron II
MnO4-(aq) + 8H+ 5e- -----> Mn2+(aq)
4H2O(l)
Fe2+(aq) ----> Fe3+(aq) + e-
(c) dichromate VI and ethanedioate
Cr2O72-(aq) + 14H+(aq) +6e-
-----> 2Cr3+(aq) +7H2O(l)
C2O42-(aq) -----> 2CO2(g) + 2e-
(d) iodine and thiosulphate
2S2O32-(aq) -----> S4O62-(aq)
+ 2e-
I2(aq) + 2e- -----> 2I-(aq)
(e) iodate and iodide
2IO3-(aq) + 12H+(aq) + 10e-
-----> I2(aq) + 6H2O(l)
2I-(aq) -----> I2(aq) + 2e-